C语言指针与数组
一个数组里面n个指针,这些指针指向n个别的数组,这n个别的数组是u8 bufx 如何定义以及初始化 不就一一赋值就可以 n是动态的话,需要你自己分配。#include "stdio.h"
/* USER CODE END 0 */
void **argv = NULL;
uint32_t argc = 0;
uint8_t bufx = {0,1,2,3};
uint8_t bufx1;
uint8_t bufx2;
uint8_t bufx3;
uint8_t *tempbuf = NULL;
void add_buffer_to_argv(uint32_t *index, uint8_t *buffer)
{
*index = *index + 1;
argv = realloc(argv,sizeof(*argv) * (*index));
if (argv == NULL) {
//your error check
}
argv[*index-1] = buffer;
}
/**
* @briefThe application entry point.
* @retval int
*/
int main(void)
{
/* USER CODE BEGIN 1 */
add_buffer_to_argv(&argc,bufx);
add_buffer_to_argv(&argc,bufx1);
add_buffer_to_argv(&argc,bufx2);
add_buffer_to_argv(&argc,bufx3);
for (uint32_t i = 0; i < argc; i ++) {
tempbuf = argv;
}
} 如果你知道n的个数的话,就直接。
uint8_t *argv = {0};
int argc = 0;
argv = buffer;
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